integral of cos(3x+2)

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∫ cos(3x+2)dx

Solution

13 sin(3x+2)+C

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Solution steps

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∫ cos(3x+2)dx

Apply u-substitution: ∫ cos(u)13 du

=∫ cos(u)13 du

Take the constant out: ∫a·f(x)dx=a·∫f(x)dx

=13 · ∫ cos(u)du

Use the common integral: ∫ cos(u)du=sin(u)

=13 sin(u)

Substitute back u=3x+2

=13 sin(3x+2)

Add a constant to the solution

=13 sin(3x+2)+C

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

integral of cos(3x+2)

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